0=y^2+64y-303

Solution for 0=y^2+64y-303 equation:

0=y^2+64y-303

We move all terms to the left:

0-(y^2+64y-303)=0

We add all the numbers together, and all the variables

-(y^2+64y-303)=0

We get rid of parentheses

-y^2-64y+303=0

We add all the numbers together, and all the variables

-1y^2-64y+303=0

a = -1; b = -64; c = +303;
Δ = b2-4ac
Δ = -642-4·(-1)·303
Δ = 5308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5308}=\sqrt{4*1327}=\sqrt{4}*\sqrt{1327}=2\sqrt{1327}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-2\sqrt{1327}}{2*-1}=\frac{64-2\sqrt{1327}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+2\sqrt{1327}}{2*-1}=\frac{64+2\sqrt{1327}}{-2}
$